0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A charged particle is projected in a magnetic field B=(3i+4j)×102T and the acceleration is found to be a=(xi+2j)m/s2. The value of x is :
  1. -8/3 m/s2
  2. 8/3 m/s2
  3. -4/3 m/s2
  4. 4/3 m/s2

A
-8/3 m/s2
B
-4/3 m/s2
C
4/3 m/s2
D
8/3 m/s2
Solution
Verified by Toppr

Was this answer helpful?
36
Similar Questions
Q1
A charged particle is projected in a magnetic field B=(3i+4j)×102T and the acceleration is found to be a=(xi+2j)m/s2. The value of x is :
View Solution
Q2
A particle is moving along a straight line such thatits velocity varies with position as shown in figure.then the acceleration of the particle at x 10 m is2015(u) x(1) -4.6 m/s2(2) -6.8 m/s2(3) -8.9 m/s2(4) -10.6 m/s2
View Solution
Q3
A car is moving on a circular road of radius r 150 m and its speed is increasing at a rate 8 m/s2. At someinstant its speed is 30 m/s, net acceleration of the car at this instant is(1) 8 m/s2(2) 6 m/s2(3) 10 m/s2(4) 14 m/s2
View Solution
Q4
Q). If the position of a particle moving laong x-axis as a function of time t isgiven by x = 6t2 m (where t is in second), then the acceleration of the particle at t = 5 s is
(1) 60 m/s2
(2) 30 m/s2
(3) 12 m/s2
(4) 5 m/s2
View Solution
Q5
Solve this:

Q47. A car is moving at a speed of 40 m/s on a circular track of radius 400 m. This speed is increasing at the rate of 3 m/s2. The acceleration of car is

(1) 4 m/s2

(2) 7 m/s2

(3) 5 m/s2

(4) 3 m/s2
View Solution