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Question

# A charged particle is released from rest in a region of steady and uniform electric and magnetic fields which are parallel to each other. The particle will move in ahelixcycloidstraight linecircle

A
straight line
B
helix
C
circle
D
cycloid
Solution
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#### →E∥→BFE=q→E$F_B= q(\vec{v} \times \vec{B}$given →v is parallel to →B⇒FB=0 since sinθ=sin0∘=0∴ the charged particle will accelerate and move in a straight line.

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