A charged particle is released from rest in a region of steady and uniform electric and magnetic fields which are parallel to each other. The particle will move in a
A
straight line
B
circle
C
helix
D
cycloid
Medium
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Solution
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Correct option is A)
E∥B FE=qE $$F_B= q(\vec{v} \times \vec{B}$$ given v is parallel to B ⇒FB=0 since sinθ=sin0∘=0 ∴ the charged particle will accelerate and move in a straight line.
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