Question

A charged particle is released from rest in a region of steady and uniform electric and magnetic fields which are parallel to each other. The particle will move in a

A
straight line
B
circle
C
helix
D
cycloid
Solution
Verified by Toppr

EB
FE=qE
$F_B= q(\vec{v} \times \vec{B}$
given v is parallel to B
FB=0 since sinθ=sin0=0
the charged particle will accelerate and move in a straight line.

Was this answer helpful?
0
Similar Questions
Q1

In a region, steady and uniform electric field and magnetic fields are present. These two fields are parallel to each other. A charged particle is released from rest in this region. The path of the particle will be a:


View Solution
Q2

A charged particle is released from rest in a region of steady uniform electric and magnetic fields which are parallel to each other. The particle will move in a?

View Solution
Q3

A charged particle is released from rest in a region of steady and uniform electric and magnetic fields, where magnetic field and electric field are parallel. The particle will follow -

View Solution
Q4

A charged particle is released from rest in a region of uniform electric field and magnetic field, which are parallel to each other. The locus of the particle will be

View Solution
Q5

A charge particle is released from rest in a region of steady and uniform electric and magnetic fields which are parallel to each other. The particle will move in a

View Solution
Solve
Guides