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Question

A charged particle moves with velocity v=a^i+d^j in a magnetic field B=A^i+D^j. The force acting on the particle has magnitude F. Then,
  1. F=0, if aD=dA
  2. F=0, if aD=dA
  3. F(a2+b2)1/2×(A2+D2)1/2
  4. F=0, if aA=dD

A
F=0, if aD=dA
B
F=0, if aD=dA
C
F=0, if aA=dD
D
F(a2+b2)1/2×(A2+D2)1/2
Solution
Verified by Toppr

F=q(v×B)

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