A charged particle of specific charge α moves with a velocity →v=v0^i in a magnetic field →B=B0√2(^j+^k). Then : (specific charge = charge per unit mass)
path of the particle is a helix
distance moved by particle intime t=πB0αisπv0B0α
path of the particle is a circle
velocity of particle after time t=πB0αis(v02^i+v02^j)
A
path of the particle is a circle
B
distance moved by particle intime t=πB0αisπv0B0α
C
path of the particle is a helix
D
velocity of particle after time t=πB0αis(v02^i+v02^j)
Open in App
Solution
Verified by Toppr
1) Path of particle in magnetic field is either circular, straight line or helix, Here charged particle is projected at an angle so path must be circular. 2) ¯¯¯v=v0¯i
Was this answer helpful?
0
Similar Questions
Q1
A charged particle of specific charge α moves with a velocity v = v0i in a magnetic field →B=B0√2(^j+^k). Then the (specific charge = charge per unit mass)
View Solution
Q2
A charged particle of specific charge α moves with a velocity →v=v0^i in a magnetic field →B=B0√2(^j+^k). Then : (specific charge = charge per unit mass)
View Solution
Q3
A charged particle of specific charge α enters in a magnetic field →B=B0√2(^j+^k) with a velocity →v=v0^i. Then (specific charge = charge per unit mass)
View Solution
Q4
A charged particle of specific charge (charge/mass) α is released from origin at time t=0 with velocity →v=v0(^i+^j) in a uniform magnetic field →B=B0^i. Coordinates of the particle at time t=πB0α are
View Solution
Q5
A charged particle of specific charge α is released from origin at time t=0 with velocity →v=v0(^i+^j) in magnetic field →B=B0^i. The coordinate of the particle at time t=πB0α will be