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# A charged particle of unit mass and unit charge moves with velocity →v=(8^i+6^j)ms−1 in a magnetic field of →B=2^kT. Choose the correct alternative(s).the path of the particle may be x2+y2−4x−21=0the time period of the particle will be 3.14sthe path of the particle may be x2+y2=25the path of the particle may be y2+z2=25

A
the path of the particle may be x2+y2=25
B
the path of the particle may be x2+y24x21=0
C
the path of the particle may be y2+z2=25
D
the time period of the particle will be 3.14s
Solution
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#### →v=8^i+6^j→B=2^km=1q=1r=mvqB=1×√82+621×2=5

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