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Question

A charged particle of unit mass and unit charge moves with velocity of v=(8^i+6^j) m/s in a magnetic field of B=2^kT. Then:
  1. the path of the particle may be x2+y24x21=0
  2. the path of the particle may be x2+y2=25
  3. the path of the particle may be y2+z2=25
  4. the time period of the particle will be 3.14s

A
the time period of the particle will be 3.14s
B
the path of the particle may be x2+y24x21=0
C
the path of the particle may be x2+y2=25
D
the path of the particle may be y2+z2=25
Solution
Verified by Toppr

r=mvqB
=82+622
=5
Both x2+y2 and x2+y24x21=0 are possible because Magnetic field is towards the positive z axis .
T=2πmqB
=2π2
=π
Particle will move in x-y plane with radius equals to 5

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