Question

This question has multiple correct options

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Updated on : 2022-09-05

Solution

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Correct options are A) , B) and C)

Time period of one revolution $=qB2πm $

$pitch=V_{h}×T=qB2πm vcosθ$

Radius of the circle $r=qBmvsinθ $

Max distance of the particle from the x-axis is 2r.

Since pitch is equal to 2r, $qB2πm vcosθ=2qBmvsinθ $

$⇒tanθ=π$.

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