Question

This question has multiple correct options

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Updated on : 2022-09-05

Solution

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Correct options are A) , B) and C)

$B=yi^+xj^ $

$f =q(v×B)=q((xi^+yj^ )×(yi^+xj^ ))=q(x_{2}−y_{2})k^$

If $x=y$, $f =q(x_{2}−y_{2})=q(0−0)=0$

If $x>y$, $f =q(x_{2}−y_{2})k^>0$

If $y>x$, $f =q(x_{2}−y_{2})k^<0$ and it points in the $−vez−$ axis.

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