A circular current loop of magnetic moment M is in an arbitrary orientation in an external magnetic field $¯ B$ . The work done to rotate the loop by 30 about an axis perpendicular to its plane is:
$M B$
$\sqrt{3} \frac{M B}{2}$
$z e r o$
$\frac{M B}{2}$

Question

A circular current loop of magnetic moment M is in an arbitrary orientation in an external magnetic field $¯ B$ . The work done to rotate the loop by 30 about an axis perpendicular to its plane is:
$M B$
$\sqrt{3} \frac{M B}{2}$
$z e r o$
$\frac{M B}{2}$

Toppr Admin · Accepted Answer

The rotation of the loop by 30-xB0- about an axis perpendicular to its plane make no change in the angle made by axis of the loop with the direction of magnetic field- therefore- the work done to rotate the loop is zero-Important point- The work done to rotate the loop the loop in magnetic field W-MB-cos-xA0-x3B8-1-x2212-cos-xA0-x3B8-2- where signs are as usual-xA0-xA0-

A circular current loop of magnetic moment M is in an arbitrary orientation in an external magnetic field ¯B. The work done to rotate the loop by 30 about an axis perpendicular to its plane is:MB√3MB2zeroMB2

A circular current loop of magnetic moment M is in an arbitrary orientation in an external magnetic field $¯ B$ . The work done to rotate the loop by 30 about an axis perpendicular to its plane is:
$M B$
$\sqrt{3} \frac{M B}{2}$
$z e r o$
$\frac{M B}{2}$