A circular loop of area 1 cm2- carrying a current of 10A- is placed in a magnetic field of 0-1T perpendicular to the plane of the loop- The torque on the loop due to the magnetic field is-

Question

Toppr Admin · Accepted Answer

As Torque is given byT-NBiAsin-x3B8-Area -1cm2Current -10AMagnetic field -0-1T-x3B8-0T-1-xD7-10-xD7-0-1-xD7-sin0-xA0- -xA0-1-xD7-0T-0-xA0-

A circular loop of area $1$ $c m^{2}$ , carrying a current of $10$ A, is placed in a magnetic field of $0.1$ T perpendicular to the plane of the loop. The torque on the loop due to the magnetic field is?

As Torque is given by
$T = N B i A sin θ$
Area $= 1 c m^{2}$
Current $= 10 A$
Magnetic field $= 0.1 T$
$θ = 0$
$T = 1 \times 10 \times 0.1 \times sin 0$
$= 1 \times 0$
$T = 0$

A circular loop of area 1 cm2, carrying a current of 10A, is placed in a magnetic field of 0.1T perpendicular to the plane of the loop. The torque on the loop due to the magnetic field is?

As Torque is given byT=NBiAsinθArea =1cm2Current =10AMagnetic field =0.1Tθ=0T=1×10×0.1×sin0 =1×0T=0

A circular loop of area $1$ $c m^{2}$ , carrying a current of $10$ A, is placed in a magnetic field of $0.1$ T perpendicular to the plane of the loop. The torque on the loop due to the magnetic field is?

As Torque is given by
$T = N B i A sin θ$
Area $= 1 c m^{2}$
Current $= 10 A$
Magnetic field $= 0.1 T$
$θ = 0$
$T = 1 \times 10 \times 0.1 \times sin 0$
$= 1 \times 0$
$T = 0$