A closely wound solenoid of 800 turns and area of cross section $2.5 \times 10^{- 4} m^{2}$ carries a current of $3.0 A$ . Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?

Question

A closely wound solenoid of 800 turns and area of cross section $2.5 \times 10^{- 4} m^{2}$ carries a current of $3.0 A$ . Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?

Toppr Admin · Accepted Answer

Given- n-800-A-2-5-xD7-10-x2212-4m2-I-3-0AA magnetic field develops along the axis of the solenoid- Therefore current-carrying solenoid acts like a bar magnet-m-nIA-800-xD7-3-xD7-2-5-xD7-10-x2212-4JT-x2212-1-xA0- -xA0- -xA0-0-6JT-x2212-1 along the axis of the solenoid-

A closely wound solenoid of 800 turns and area of cross section 2.5×10−4m2 carries a current of 3.0A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?

Given: n=800,A=2.5×10−4m2,I=3.0AA magnetic field develops along the axis of the solenoid. Therefore current-carrying solenoid acts like a bar magnet.m=nIA=800×3×2.5×10−4JT−1 =0.6JT−1 along the axis of the solenoid.

A closely wound solenoid of 800 turns and area of cross section $2.5 \times 10^{- 4} m^{2}$ carries a current of $3.0 A$ . Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?

Given: $n = 800,$
$A = 2.5 \times 10^{- 4} m^{2},$
$I = 3.0 A$
A magnetic field develops along the axis of the solenoid. Therefore current-carrying solenoid acts like a bar magnet.
$m = n I A = 800 \times 3 \times 2.5 \times 10^{- 4} J T^{- 1}$

$= 0.6 J T^{- 1}$ along the axis of the solenoid.