A coil has resistance 30 ohm and inductive reactance 20 ohm 50 Hz frequency- If an ac of 200 volt- 100 Hz- is connected across the coil- the current in the coil will be4-0 A2-0 A8-0 Adisplaystylefrac-20-sqrt-13- A

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Toppr Admin · Accepted Answer

If -x3C9-50-xD7-2-x3C0- -xA0-then -xA0-x3C9-L-20-x3A9-If -x3C9-x2032-100-xD7-2-x3C0- -xA0-then -xA0-x3C9-x2032-L-40-x3A9-I-200Z200-x221A-R2-x3C9-x2032-L-2-200-x221A-302-40-2I-4A-

A coil has resistance $30 o h m$ and inductive reactance $20 o h m$ at $50 H z$ frequency. If an $a c$ source of $200 v o l t, 100 H z$ , is connected across the coil, the current in the coil will be
$4.0 A$
$2.0 A$
$8.0 A$
$\frac{20}{\sqrt{13}} A$

If $ω = 50 \times 2 π$ then $ω L = 20 Ω$
If $ω^{'} = 100 \times 2 π$ then $ω^{'} L = 40 Ω$
$I = \frac{200}{Z} \frac{200}{\sqrt{R^{2} + {(ω^{'} L)}^{2}}} = \frac{200}{\sqrt{30^{2} + {(40)}^{2}}}$
$I = 4 A$ .

A coil has resistance 30ohm and inductive reactance 20ohm at 50Hz frequency. If an ac source of 200volt,100Hz, is connected across the coil, the current in the coil will be4.0A2.0A8.0A20√13A

If ω=50×2π then ωL=20ΩIf ω′=100×2π then ω′L=40ΩI=200Z200√R2+(ω′L)2=200√302+(40)2I=4A.

A coil has resistance $30 o h m$ and inductive reactance $20 o h m$ at $50 H z$ frequency. If an $a c$ source of $200 v o l t, 100 H z$ , is connected across the coil, the current in the coil will be
$4.0 A$
$2.0 A$
$8.0 A$
$\frac{20}{\sqrt{13}} A$

If $ω = 50 \times 2 π$ then $ω L = 20 Ω$
If $ω^{'} = 100 \times 2 π$ then $ω^{'} L = 40 Ω$
$I = \frac{200}{Z} \frac{200}{\sqrt{R^{2} + {(ω^{'} L)}^{2}}} = \frac{200}{\sqrt{30^{2} + {(40)}^{2}}}$
$I = 4 A$ .