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Question

A coin is placed at the bottom of a beaker containing water (refractive index =4/3) to a depth of 12cm. By what height the coin appears to be raised when seen from vertically above?
  1. 9 cm
  2. 16 cm
  3. 3 cm
  4. 4 cm

A
9 cm
B
16 cm
C
3 cm
D
4 cm
Solution
Verified by Toppr

RI=real depthapparent depth

Substituting, 43=12apparentdepth

Therefore, apparent depth=12×34=9

The height by which it appears to be raised is 129=3cm

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