Question

A coin is tossed five times, find the probability of getting no head.

• A. $\frac{1}{30}$
• B. $\frac{5}{32}$
• C. $0.4$
• D. $\frac{1}{32}$

Answer 1

Answer: (D)

Given: Coin tossed 5 times

To find: the probability of getting no head

Sol: The coin is tossed 5 times, hence $n\left(S\right)=2^5=32$

As we need to find the probability of getting no head, which is possible only in one case i.e., {TTTTT}. Hence $n\left(E\right)=1$

Therefore, the probability of getting no head, $\frac{n\left(E\right)}{n\left(S\right)}=\frac{1}{32}$