A compound M-pX-q has cubic close packing -ccp- arrangement of X- Its unit cell structure is shown above- The empirical formula of the compound is-MX-2M-2XM-5X-14-MX

Question

Toppr Admin · Accepted Answer

Number of atoms of M -1-4-xD7-14-2Number of atoms of X -18-xD7-8-6-xD7-12-4Therefore- the empirical formula is MX2

A compound $M_{p} X_{q}$ has cubic close packing $(c c p)$ arrangement of X. Its unit cell structure is shown above. The empirical formula of the compound is:

$M X_{2}$
$M_{2} X$
$M_{5} X_{14}$
$M X$

Number of atoms of M $= 1 + 4 \times \frac{1}{4} = 2$

Number of atoms of X $= \frac{1}{8} \times 8 + 6 \times \frac{1}{2} = 4$

Therefore, the empirical formula is $M X_{2}$

A compound MpXq has cubic close packing (ccp) arrangement of X. Its unit cell structure is shown above. The empirical formula of the compound is:MX2M2XM5X14MX

Number of atoms of M =1+4×14=2Number of atoms of X =18×8+6×12=4Therefore, the empirical formula is MX2

A compound $M_{p} X_{q}$ has cubic close packing $(c c p)$ arrangement of X. Its unit cell structure is shown above. The empirical formula of the compound is:

$M X_{2}$
$M_{2} X$
$M_{5} X_{14}$
$M X$

Number of atoms of M $= 1 + 4 \times \frac{1}{4} = 2$

Number of atoms of X $= \frac{1}{8} \times 8 + 6 \times \frac{1}{2} = 4$

Therefore, the empirical formula is $M X_{2}$