A concave lens of focal length 15cm forms an image 10 cm from the lens . How far is the object placed from the lens? Draw the ray diagram.

Name: A concave lens of focal length 15cm forms an image 10 cm from the lens . How far is the object placed from the lens? Draw the ray diagram.
Uploaded: 2020-01-06
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Question

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Answer 1

Given: $f = - 15$
$v = - 10$
From mirror formula, $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
$\frac{1}{- 1 0} - \frac{1}{u} = \frac{1}{- 1 5}$
$\frac{1}{u} = \frac{1}{1 5} - \frac{1}{1 0}$
$u = - 30 c m$

Answer 2

Given:

f = - 15

v = - 10

From mirror formula,

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

\frac{1}{- 1 0} - \frac{1}{u} = \frac{1}{- 1 5}

\frac{1}{u} = \frac{1}{1 5} - \frac{1}{1 0}

u = - 30 c m

A concave lens of focal length 15cm forms an image 10 cm from the lens . How far is the object placed from the lens? Draw the ray diagram.

Given: $f = - 15$
$v = - 10$
From mirror formula, $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
$\frac{1}{- 1 0} - \frac{1}{u} = \frac{1}{- 1 5}$
$\frac{1}{u} = \frac{1}{1 5} - \frac{1}{1 0}$
$u = - 30 c m$

An object is placed at $30 c m$ from a convex lens and its real image is formed at $20 c m$ away from the lens. Calculate the focal length of convex lens. Draw ray diagram also.

A concave lens of focal length 15 cm form an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram also.

A concave lens has focal length of $15 c m$ . At what distance should the object from the lens be placed so that it forms an erect and virtual image at $10 c m$ from the lens?

A concave lens of $20 c m$ focal length forms an image $15 c m$ from the lens. Calculate the object distance.

A diverging lens of 20 cm focal length forms on image 15 cm from the lens. What is the distance of the object from the lens?

Revise with Concepts

Problems on Lens and Magnification Formula

A concave lens of focal length 15cm forms an image 10 cm from the lens . How far is the object placed from the lens? Draw the ray diagram.

Given: f=−15 v=−10From mirror formula, v1​−u1​=f1​ −101​−u1​=−151​ u1​=151​−101​ u=−30 cm

An object is placed at 30cm from a convex lens and its real image is formed at 20cm away from the lens. Calculate the focal length of convex lens. Draw ray diagram also.

A concave lens of focal length 15 cm form an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram also.

A concave lens has focal length of 15 cm. At what distance should the object from the lens be placed so that it forms an erect and virtual image at 10 cm from the lens?

A concave lens of 20cm focal length forms an image 15cm from the lens. Calculate the object distance.

A diverging lens of 20 cm focal length forms on image 15 cm from the lens. What is the distance of the object from the lens?

Revise with Concepts

Problems on Lens and Magnification Formula

Given: $f = - 15$
$v = - 10$
From mirror formula, $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
$\frac{1}{- 1 0} - \frac{1}{u} = \frac{1}{- 1 5}$
$\frac{1}{u} = \frac{1}{1 5} - \frac{1}{1 0}$
$u = - 30 c m$

An object is placed at $30 c m$ from a convex lens and its real image is formed at $20 c m$ away from the lens. Calculate the focal length of convex lens. Draw ray diagram also.

A concave lens has focal length of $15 c m$ . At what distance should the object from the lens be placed so that it forms an erect and virtual image at $10 c m$ from the lens?

A concave lens of $20 c m$ focal length forms an image $15 c m$ from the lens. Calculate the object distance.