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Question

A concave mirror has radius of curvature of 40cm. It is at the bottom of a glass that has water filled up to 5cm (see figure). If a small particle is floating on the surface of water, its image as seen, from directly above the glass, is at a distance d from the surface of water. The value of d is close to : (Refractive index of water =1.33)
1614884_f98c9c9cbbf1450f8b2c2bcf14a16ba8.png
  1. 8.8cm
  2. 11.7cm
  3. 6.7cm
  4. 13.4cm

A
6.7cm
B
13.4cm
C
8.8cm
D
11.7cm
Solution
Verified by Toppr

The correct option is A 8.8cm
Light incident from particle P will be reflected at mirror
u=5cm,f=R2=20cm
1v+1u=1f
v1=+203cm
This image will act as object for light getting refracted at water surface
So, object distance d=5+203=353cm
below water surface,
After refraction, final image is at
d=d(μ2μ1)
=(353)(14/3)
=354=8.75cm
8.8cm
1248238_1614884_ans_2f97824ece7946fcac4332b4103be7b8.PNG

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