Question

# A concave mirror of radius R is kept on a horizontal table (figure). Water (refractive index = μ) is poured into it up to a height h. Where should an object be placed so that its image is formed on itself? Solution
Verified by Toppr

#### Let the object be placed at a height x above the surface of the water.The apparent position of the object with respect to mirror should be at the centre of curvature so that the image is formed at the same position.Since, Real depthApparent depth=1μ (with respect to mirror)Now, xR−h=1μ⇒x=R−hμ 2
Similar Questions
Q1

The convex surface of a thin concavo-convex lens of glass of refractive index 1.5 has a radius of curvature 20 cm. The concave surface has a radius of curvature 60 cm. The convex side is silvered and placed on a horizontal surface as shown in figure. (a) Where should a pin be placed on the axis so that its image is formed at the same place? (b) If the concave part is filled with water (μ = 4/3), find the distance through which the pin should be moved so that the image of the pin again coincides with the pin.
Figure

View Solution
Q2

Where would an object be placed in a medium of refractive index μ1 , so that its real image is formed at equidistant from sphere (of radius R and refractive index μ2) which is also placed in the medium of refractive index μ1 as shown in figure? View Solution
Q3

A concave morror of radius R is kept on a horizontal table(figure). Water (refractiveindex=μ) is poured into it upto a height h. Where should an object be placed (its distance from the water source) so that its final image is formed on itself. Consider two cases
(i) h 0
(ii) in terms of h View Solution
Solve
Guides