A condenser of 250mu F is connected in parallel to a cell of inductance 0-16 mH- while its effective resistance is while its- Determine the resonant frequency-

Question

Toppr Admin · Accepted Answer

Correct option is C- -8-times 10-5- HzGiven-160-Capacitance- -C- 250-mu F- 250-times 10-6- F-Inductance - -L-0-16mH- 0-16 -times 10-3-H-Resonant frequency -160- -f-dfrac1-2-pi -sqrt-LC- -dfrac1-2-times 3-14-times -sqrt-250-times -160-10-6- -times 0-16 -times 10-3- 8-times 10-5 Hz-

A condenser of $$250\mu F$$ is connected in parallel to a cell of inductance $$0.16$$ mH, while its effective resistance is while its. Determine the resonant frequency.

Correct option is C. $$8\times 10^5$$ Hz
Given
Capacitance, $$C= 250\mu F= 250\times 10^{-6} F$$
Inductance , $$L=0.16mH= 0.16 \times 10^{-3}H$$

Resonant frequency , $$f=\dfrac1{2\pi \sqrt{LC}}= \dfrac1{2\times 3.14\times \sqrt{250\times 10^{-6} \times 0.16 \times 10^{-3}}}= 8\times 10^5 Hz$$

A condenser of $$250\mu F$$ is connected in parallel to a cell of inductance $$0.16$$ mH, while its effective resistance is while its. Determine the resonant frequency.

Correct option is C. $$8\times 10^5$$ HzGiven Capacitance, $$C= 250\mu F= 250\times 10^{-6} F$$Inductance , $$L=0.16mH= 0.16 \times 10^{-3}H$$Resonant frequency , $$f=\dfrac1{2\pi \sqrt{LC}}= \dfrac1{2\times 3.14\times \sqrt{250\times 10^{-6} \times 0.16 \times 10^{-3}}}= 8\times 10^5 Hz$$

Correct option is C. $$8\times 10^5$$ Hz
Given
Capacitance, $$C= 250\mu F= 250\times 10^{-6} F$$
Inductance , $$L=0.16mH= 0.16 \times 10^{-3}H$$

Resonant frequency , $$f=\dfrac1{2\pi \sqrt{LC}}= \dfrac1{2\times 3.14\times \sqrt{250\times 10^{-6} \times 0.16 \times 10^{-3}}}= 8\times 10^5 Hz$$