Question

A conducing rod $AC$ of length $4l$ is rotated about a point $O$ in a uniform magnetic field $\overrightarrow{B}$ direction into the paper $AO=l$ and $OC=3l$. Then

• A. $V_A-V_O=\frac{B\omega l^2}{2}$
• B. $V_O-V_C=\frac{7}{2}\omega l^{2}2$
• C. $V_A-V_C=4\omega l^{2}2$
• D. $V_C-V_O=\frac{9}{2}\omega l^2$

Answer 1

Answer: (A)