A conducting rod AB moves parallel to X-axis in a uniform magnetic field, pointing in the positive X-direction. The end A of the rod gets

Question

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Answer 1

According to right hand palm rule, the Lorentz force on free electrons in the conductor will be directed towards end B. Hence, the end A gets positively charged.

Answer 2

According to right hand palm rule, the Lorentz force on free electrons in the conductor will be directed towards end B. Hence, the end A gets positively charged.

A conducting rod AB moves parallel to X-axis in a uniform magnetic field, pointing in the positive X-direction. The end A of the rod gets

positively charged

negatively charged

neutral

first positively charged and then negatively charged

According to right hand palm rule, the Lorentz force on free electrons in the conductor will be directed towards end B. Hence, the end A gets positively charged.

If a magnetic field $B$ points in the positive x direction, what is the magnitude of the emf developed in the wire when $B$ increases at the rate of $3 m$ $T s^{- 1}$ ?

The conducting rod $a b$ , as shown in figure makes contact with metal rails $c a$ and $d b$ . The apparatus is in a uniform magnetic field of $0.800 T$ , perpendicular to the plane of the figure. In what direction does the current flow in the rod?

In the figure magnetic field points into the plane of paper and the conducting rod of length $l$ is moving in this field such that the lowest point has a velocity $v_{1}$ and the topmost point has the velocity $v_{2} (v_{2} > v_{1})$ . The emf induced is given by :

A conducting rod $A B$ moves parallel to the x-axis in a uniform magnetic field pointing in the positive z direction. The end $A$ of the rod gets positively charged. explain.

A conducting rod PQ is moving parallel to X-axis in a uniform magnetic filed directed in positive Y-direction. The end P of the rod will become

Revise with Concepts

Magnetic Field and Magnetic Force

A conducting rod AB moves parallel to X-axis in a uniform magnetic field, pointing in the positive X-direction. The end A of the rod gets

positively charged

negatively charged

neutral

first positively charged and then negatively charged

According to right hand palm rule, the Lorentz force on free electrons in the conductor will be directed towards end B. Hence, the end A gets positively charged.

If a magnetic field B points in the positive x direction, what is the magnitude of the emf developed in the wire when B increases at the rate of 3m Ts−1?

The conducting rod ab, as shown in figure makes contact with metal rails ca and db. The apparatus is in a uniform magnetic field of 0.800T, perpendicular to the plane of the figure. In what direction does the current flow in the rod?

In the figure magnetic field points into the plane of paper and the conducting rod of length l is moving in this field such that the lowest point has a velocity v1​ and the topmost point has the velocity v2​(v2​>v1​). The emf induced is given by :

A conducting rod AB moves parallel to the x-axis in a uniform magnetic field pointing in the positive z direction. The end A of the rod gets positively charged. explain.

A conducting rod PQ is moving parallel to X-axis in a uniform magnetic filed directed in positive Y-direction. The end P of the rod will become

Revise with Concepts

Magnetic Field and Magnetic Force

If a magnetic field $B$ points in the positive x direction, what is the magnitude of the emf developed in the wire when $B$ increases at the rate of $3 m$ $T s^{- 1}$ ?

The conducting rod $a b$ , as shown in figure makes contact with metal rails $c a$ and $d b$ . The apparatus is in a uniform magnetic field of $0.800 T$ , perpendicular to the plane of the figure. In what direction does the current flow in the rod?

In the figure magnetic field points into the plane of paper and the conducting rod of length $l$ is moving in this field such that the lowest point has a velocity $v_{1}$ and the topmost point has the velocity $v_{2} (v_{2} > v_{1})$ . The emf induced is given by :

A conducting rod $A B$ moves parallel to the x-axis in a uniform magnetic field pointing in the positive z direction. The end $A$ of the rod gets positively charged. explain.