A conductor with a cavity is charged positively and its surface charge density is σ. If E and V represent the electric field and potential, then inside the cavity:
and V=0
E=0 and V=0
E=0 and σ=constant
V=0 and σ= constant
E=0 and V= constant
A
V=0 and σ= constant
B
E=0 and V= constant
C
E=0 and σ=constant
D
and V=0
E
E=0 and V=0
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Solution
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Surface charge density =σ. Inside the surface, the electric field is zero. ⇒Einside=0 ∵Vinside=Vsurface The potential inside the surface of charged sphere is constant. ∴E=0,V=constant.
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