A cone of base radius R and height h is located in a uniform electric field overrightarrow-E- parallel to its base- The electric flux entering the cone is-4 E h R2 E h Rdisplaystyle dfrac-1-2- E h RE h R

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A cone of base radius $R$ and height $h$ is located in a uniform electric field $\to E$ parallel to its base. The electric flux entering the cone is:
$4 E h R$
$2 E h R$
$\frac{1}{2}$ $E h R$
$E h R$

We know that,
$ϕ = E . A C o s θ$
Flux crossing through the area of cone parallel to the electric field which is nothing but a right angle triangle having base $2 R$ and height $h$
therefore, $ϕ = E h R$

A cone of base radius R and height h is located in a uniform electric field →E parallel to its base. The electric flux entering the cone is:4EhR2EhR12 EhREhR

We know that,ϕ=E.ACosθFlux crossing through the area of cone parallel to the electric field which is nothing but a right angle triangle having base 2R and height htherefore, ϕ=EhR

A cone of base radius $R$ and height $h$ is located in a uniform electric field $\to E$ parallel to its base. The electric flux entering the cone is:
$4 E h R$
$2 E h R$
$\frac{1}{2}$ $E h R$
$E h R$

We know that,
$ϕ = E . A C o s θ$
Flux crossing through the area of cone parallel to the electric field which is nothing but a right angle triangle having base $2 R$ and height $h$
therefore, $ϕ = E h R$