A conical container of base radius -r- and height -h- is full of water which is poured into a cylindrical container of radius mr then it will occupy a height equal to displaystyle 3m-2-h displaystyle frac-h-3m-2- displaystyle frac-3h-m- displaystyle frac-mh-3-

Question

A conical container of base radius -r- and height -h- is full of water which is poured into a cylindrical container of radius mr then it will occupy a height equal to displaystyle 3m-2-h  displaystyle frac-h-3m-2-  displaystyle frac-3h-m-  displaystyle frac-mh-3-

Toppr Admin · Accepted Answer

Given base radius and height of conical container is r and h respt.
Then volume of conical container= $\frac{1}{3} π r^{2} h c m^{3}$
The conical container full of water which is poured into cylindrical container of radius mr
Then volume of cylindrical container= $π (m r)^{2} H$ ( where H is the height of cylindrical container)
$∴ π (m r)^{2} H = \frac{1}{2} π r^{2} h \Rightarrow H = \frac{h}{3 m^{2}}$
Then height of cylindrical container= $\frac{h}{3 m^{2}}$

A conical container of base radius 'r' and height 'h' is full of water which is poured into a cylindrical container of radius mr then it will occupy a height equal to3m2hh3m23hmmh3

A conical container of base radius 'r' and height 'h' is full of water which is poured into a cylindrical container of radius mr then it will occupy a height equal to
$3 m^{2} h$
$\frac{h}{3 m^{2}}$
$\frac{3 h}{m}$
$\frac{m h}{3}$