A conical cup has a circular base with diameter $21 c m$ and height $1.8 d m$ . How much oil can it contain?

Question

A conical cup has a circular base with diameter 21-cm and height 1-8-dm- How much oil can it contain-2079-ml2077-ml2069-ml2078-ml

Toppr Admin · Accepted Answer

Diameter-2 radiusr-10-5-h-1-8-xA0-dm-18-xA0-cmVolume of cone -13-x3C0-r2h-13-x3C0-10-52-18-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-2079-xA0-ml

A conical cup has a circular base with diameter $21 c m$ and height $1.8 d m$ . How much oil can it contain?
$2079 m l$
$2077 m l$
$2069 m l$
$2078 m l$

$d i a m e t e r = 2$ radius
$r = 10.5, h = 1.8 d m = 18 c m$
Volume of cone $= \frac{1}{3} π r^{2} h = \frac{1}{3} π ({10.5}^{2}) (18)$
$= 2079 m l$

A conical cup has a circular base with diameter 21cm and height 1.8dm. How much oil can it contain?2079ml2077ml2069ml2078ml

diameter=2 radiusr=10.5,h=1.8 dm=18 cmVolume of cone =13πr2h=13π(10.52)(18) =2079 ml

A conical cup has a circular base with diameter $21 c m$ and height $1.8 d m$ . How much oil can it contain?
$2079 m l$
$2077 m l$
$2069 m l$
$2078 m l$

$d i a m e t e r = 2$ radius
$r = 10.5, h = 1.8 d m = 18 c m$
Volume of cone $= \frac{1}{3} π r^{2} h = \frac{1}{3} π ({10.5}^{2}) (18)$
$= 2079 m l$