Question

A conical flask of base radius r and height h is full of milk The milk is now poured into a cylindrical flask of radius 2r What is the height to which the milk will rise in the flask?

• A. $\frac{h}{3}$
• B. $\frac{h}{6}$
• C. $\frac{h}{9}$
• D. $\frac{h}{12}$

Answer 1

Answer: (D)

Given radius and height of conical flask is r and h

Then volume of conical flask =volume of milk=$\frac{1}{3}\pi r^{2}h$

Milk poured in cylindrical flask radius 2r and let height is H

Then volume of cylindrical flask =$\pi (2r{)}^{2}H=4\pi r^{2}H$

$\therefore 4\pi r^{2}H=\frac{1}{3}\pi r^{2}h$

$\Rightarrow H=\frac{h}{12}$