A conical pit of diameter 3-5m is 12 m deep- What is its capacity in kilolitres-

Question

Toppr Admin · Accepted Answer

We have-r-dfrac-3-5-2-dfrac-7-4-m and -h-12-m-therefore V-dfrac-1-3-pi r-2h-dfrac-1-3-times -dfrac-22-7-times -dfrac-7-4-times -dfrac-7-4-times 12m-3-38-5m-3-38-5- Kilolitres-

A conical pit of top diameter $$3.5$$m is $$12$$ m deep. What is its capacity in kilolitres?

We have,
$$r=\dfrac{3.5}{2}=\dfrac{7}{4}$$m and $$h=12$$m

$$\therefore V=\dfrac{1}{3}\pi r^2h=\dfrac{1}{3}\times \dfrac{22}{7}\times \dfrac{7}{4}\times \dfrac{7}{4}\times 12m^3=38.5m^3=38.5$$ Kilolitres.

A conical pit of top diameter $$3.5$$m is $$12$$ m deep. What is its capacity in kilolitres?

We have,$$r=\dfrac{3.5}{2}=\dfrac{7}{4}$$m and $$h=12$$m$$\therefore V=\dfrac{1}{3}\pi r^2h=\dfrac{1}{3}\times \dfrac{22}{7}\times \dfrac{7}{4}\times \dfrac{7}{4}\times 12m^3=38.5m^3=38.5$$ Kilolitres.

We have,
$$r=\dfrac{3.5}{2}=\dfrac{7}{4}$$m and $$h=12$$m

$$\therefore V=\dfrac{1}{3}\pi r^2h=\dfrac{1}{3}\times \dfrac{22}{7}\times \dfrac{7}{4}\times \dfrac{7}{4}\times 12m^3=38.5m^3=38.5$$ Kilolitres.