A constant torque acting on a uniform circular wheel changes its angular momentum from $A_{o}$ to ${4 A}_{o}$ in $4$ seconds. The magnitude of this torque is:

Question

A constant torque acting on a uniform circular wheel changes its angular momentum from L to 4L in 4 seconds- The torque acting on it is-4L12Ldfrac-3-4- Ldfrac-4-3- L

Toppr Admin · Accepted Answer

As we know that- -x3C4-x394-L-x394-tSo- -x3C4-4L-x2212-L4-3L4

A constant torque acting on a uniform circular wheel changes its angular momentum from $L$ to $4 L$ in $4$ seconds. The torque acting on it is:
$4 L$
$12 L$
$\frac{3}{4} L$
$\frac{4}{3} L$

As we know that, $τ = \frac{Δ L}{Δ t}$

So, $τ = \frac{4 L - L}{4} = \frac{3 L}{4}$

A constant torque acting on a uniform circular wheel changes its angular momentum from L to 4L in 4 seconds. The torque acting on it is:4L12L34L43L

As we know that, τ=ΔLΔtSo, τ=4L−L4=3L4

A constant torque acting on a uniform circular wheel changes its angular momentum from $L$ to $4 L$ in $4$ seconds. The torque acting on it is:
$4 L$
$12 L$
$\frac{3}{4} L$
$\frac{4}{3} L$

As we know that, $τ = \frac{Δ L}{Δ t}$

So, $τ = \frac{4 L - L}{4} = \frac{3 L}{4}$