A converging lens of focal length f is used as simple microscope- If the least distance of distinct version of the observer is D and the lens is held close to the eye- the magnifying power of the lens is-D-2f-D-f-dfrac-D-f- - 1-f-D-

Question

Toppr Admin · Accepted Answer

The magnifying power-M- of the lens is given by-M-leastdistanceofdistinctversionfocallengthoflensTherefore- as per given problem-M-DfHence- option D is correct-

A converging lens of focal length $f$ is used as simple microscope. If the least distance of distinct version of the observer is $D$ and the lens is held close to the eye, the magnifying power of the lens is
$D / 2 f$
$D / f$
$\frac{D}{f} - 1$
$f / D$

The magnifying power(M) of the lens is given by,
$M = \frac{l e a s t d i s t a n c e o f d i s t i n c t v e r s i o n}{f o c a l l e n g t h o f l e n s}$
Therefore, as per given problem,
$M = \frac{D}{f}$

Hence, option D is correct.

A converging lens of focal length f is used as simple microscope. If the least distance of distinct version of the observer is D and the lens is held close to the eye, the magnifying power of the lens isD/2fD/fDf−1f/D

The magnifying power(M) of the lens is given by,M=leastdistanceofdistinctversionfocallengthoflensTherefore, as per given problem,M=DfHence, option D is correct.

A converging lens of focal length $f$ is used as simple microscope. If the least distance of distinct version of the observer is $D$ and the lens is held close to the eye, the magnifying power of the lens is
$D / 2 f$
$D / f$
$\frac{D}{f} - 1$
$f / D$

The magnifying power(M) of the lens is given by,
$M = \frac{l e a s t d i s t a n c e o f d i s t i n c t v e r s i o n}{f o c a l l e n g t h o f l e n s}$
Therefore, as per given problem,
$M = \frac{D}{f}$

Hence, option D is correct.