A convex lens made of glass of mu-1-5 has a focal length f in air- When it is completely immersed in a liquid of mu -2 its focal length and nature will be-2f- converging3f- converging2f- diverging3f- diverging

Question

Toppr Admin · Accepted Answer

Let k-1R1-x2212-1R2So- 1f-x3BC-x2212-1-kor- 1f-32-x2212-1-kor- k- 2f

A convex lens made of glass of $μ = 1.5$ has a focal length $f$ in air. When it is completely immersed in a liquid of $μ$ $= 2$ its focal length and nature will be:
$2 f$ , converging
$3 f$ , converging
$2 f$ , diverging
$3 f$ , diverging

Let $k =$ $\frac{1}{R_{1}} - \frac{1}{R_{2}}$

So, $\frac{1}{f} = (μ - 1) k$

or, $\frac{1}{f} = (\frac{3}{2} - 1) k$

or, $k =$ $\frac{2}{f}$

A convex lens made of glass of μ=1.5 has a focal length f in air. When it is completely immersed in a liquid of μ =2 its focal length and nature will be:2f, converging3f, converging2f, diverging3f, diverging

Let k=1R1−1R2So, 1f=(μ−1)kor, 1f=(32−1)kor, k= 2f

A convex lens made of glass of $μ = 1.5$ has a focal length $f$ in air. When it is completely immersed in a liquid of $μ$ $= 2$ its focal length and nature will be:
$2 f$ , converging
$3 f$ , converging
$2 f$ , diverging
$3 f$ , diverging

Let $k =$ $\frac{1}{R_{1}} - \frac{1}{R_{2}}$

So, $\frac{1}{f} = (μ - 1) k$

or, $\frac{1}{f} = (\frac{3}{2} - 1) k$

or, $k =$ $\frac{2}{f}$