A convex lens of focal length 6-25 cm is used as a simple microscope- To obtain maximum magnification- the object distance should be5-25 cm4-25cm5-00cm4-50cm

Question

Toppr Admin · Accepted Answer

From- 1v-x2212-1u-1f-xA0-We have-xA0-1-x2212-D-1uo-1f-x21D2-1uo-1D-1f-x21D2-1uo-125-16-25-15-x21D2-uo-5

A convex lens of focal length $6.25 c m$ is used as a simple microscope. To obtain maximum magnification, the object distance should be
$5.25 c m$
$4.25 c m$
$5.00 c m$
$4.50 c m$

From: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
We have: $\frac{1}{- D} + \frac{1}{u_{o}} = \frac{1}{f}$

$\Rightarrow \frac{1}{u_{o}} = \frac{1}{D} + \frac{1}{f}$

$\Rightarrow \frac{1}{u_{o}} = \frac{1}{25} + \frac{1}{6.25} = \frac{1}{5}$

$\Rightarrow u_{o} = 5$

A convex lens of focal length 6.25cm is used as a simple microscope. To obtain maximum magnification, the object distance should be5.25cm4.25cm5.00cm4.50cm

From: 1v−1u=1f We have: 1−D+1uo=1f⇒1uo=1D+1f⇒1uo=125+16.25=15⇒uo=5

A convex lens of focal length $6.25 c m$ is used as a simple microscope. To obtain maximum magnification, the object distance should be
$5.25 c m$
$4.25 c m$
$5.00 c m$
$4.50 c m$

From: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
We have: $\frac{1}{- D} + \frac{1}{u_{o}} = \frac{1}{f}$

$\Rightarrow \frac{1}{u_{o}} = \frac{1}{D} + \frac{1}{f}$

$\Rightarrow \frac{1}{u_{o}} = \frac{1}{25} + \frac{1}{6.25} = \frac{1}{5}$

$\Rightarrow u_{o} = 5$