A convex mirror has a radius of curvature of 22 cm. If an object is placed 14 cm away from the mirror then its image is formed at -
6.2 cm on the back side of the mirror.
6.2 cm on the front side of the mirror
51.3 cm on the front of the mirror.
51.3 cm on the back side of the mirror.

Question

A convex mirror has a radius of curvature of 22 cm. If an object is placed 14 cm away from the mirror then its image is formed at -
6.2 cm on the back side of the mirror.
6.2 cm on the front side of the mirror
51.3 cm on the front of the mirror.
51.3 cm on the back side of the mirror.

Toppr Admin · Accepted Answer

Given- -Radius of curvature- R-22cm -Focal length- f-R2-x2212-222-x2212-11cm -Positon of object- u-x2212-14cm -1f-1v-1u-1-x2212-1-1v-1-x2212-14-v-x2212-51-33cm-Hence-xA0-51-3 cm on the front of the mirror-

A convex mirror has a radius of curvature of 22 cm. If an object is placed 14 cm away from the mirror then its image is formed at -6.2 cm on the back side of the mirror.6.2 cm on the front side of the mirror51.3 cm on the front of the mirror.51.3 cm on the back side of the mirror.

Given, Radius of curvature, R=22cm Focal length. f=R2=−222=−11cm Positon of object, u=−14cm 1f=1v+1u 1−1=1v+1−14 v=−51.33cm Hence, 51.3 cm on the front of the mirror.

A convex mirror has a radius of curvature of 22 cm. If an object is placed 14 cm away from the mirror then its image is formed at -
6.2 cm on the back side of the mirror.
6.2 cm on the front side of the mirror
51.3 cm on the front of the mirror.
51.3 cm on the back side of the mirror.

Given,

Radius of curvature, $R = 22 c m$

Focal length. $f = \frac{R}{2} = \frac{- 22}{2} = - 11 c m$

Positon of object, $u = - 14 c m$

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$\frac{1}{- 1} = \frac{1}{v} + \frac{1}{- 14}$

$v = - 51.33 cm$

Hence, 51.3 cm on the front of the mirror.