A copper wire of cross-sectional area 2.0mm2, resistivity = 1.7×10−8Ωm, carries a current of 1 A. The electric field in the copper wire is:
8.5×10−4V/m
8.5×10−3V/m
8.5×10−5V/m
8.5×10−2V/m
A
8.5×10−4V/m
B
8.5×10−3V/m
C
8.5×10−2V/m
D
8.5×10−5V/m
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Solution
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from given data A=2mm2 ρ=1.7×10−8Ωm. i=1A V=iR ( from ohms law.) V=i×ρlA E.l=i×ρlA
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