A cube of side b has a charge q at each of its vertices. Determine the potential and electric field due to this charge array at the centre of the cube.
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Diagonal of the cube face, d=(b2+b2)=b2 Diagonal of cube l=(d2+b2)=b3 Distance between center of cube and vertices, r=l/2=b3/2 Potential, v=8q/4πϵor=4q/3πϵob (8 due to presence of 8 charges at the vertices) by symmetry of charge electric field, E=0.
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