We have,
Side of cubical block$$=7\,cm.$$
Then radius of hemisphere $$=\dfrac{7}{2}\,cm=3.5\,cm.$$
Then,
Total surface area of the solid=Total surface area of cube-Area of base of hemisphere +curved surface area of hemisphere.
$$ \Rightarrow TSA=6\times {{7}^{2}}-\pi \times {{\left( 3.5
\right)}^{2}}+2\pi {{\left( 3.5 \right)}^{2}} $$
$$ \Rightarrow TSA=332.465\,\,\,c{{m}^{2}}. $$
Hence, this is the
answer.