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Question

A current carrying loop of radius 2 cm has 4A current flowing in an anti-clockwise direction. The plane of the loop makes an angle of θ with the direction of the magnetic field which is in an upward direction. the value of the magnetic field is 0.7 Tesla.if potential energy of loop in magnetic field is ≈0.01 J, then value of θ is:450600300None of these

A
None of these
B
600
C
300
D
450
Solution
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Potential energy =μB=μBcosθ where μ=magnetic momentμ=iA where A= Area of looppE=iAcosθ×B=0.010.7×4×π×4×10−4cosθ=0.01cosθ=0.01×10−416π×0.7=10050×0.7=20.7cosθ>1 is not possible.So option C is correct.

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