A current flowing through a wire depends on time as I=3t2+2t+5. The charge flowing through the cross section of the wire in time from t=0 to t=2sec is
22C
20C`
18C
5C
A
20C`
B
18C
C
5C
D
22C
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Solution
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Step 1: Current through the wire
We know that,
I=dqdt
⇒dq=Idt....(1)
Step 2: Integrating the equation (1) with proper limits
Time interval: t=0s to t=2s
∫dq=∫20Idt
I=3t2+2t+5
⇒q=∫20(3t2+2t+5)dt=[t3+t2+5t]20=(8+4+10)=22C
Hence Option (A) is correct.
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