A current I flows through a uniform wire of diameter d when the mean electron drift velocity is
V. The same current will flow through a wire of diameter d/2 made of the same material if the
mean drift velocity of the electron is:

Question

Toppr Admin · Accepted Answer

The relation between current and drift velocity is-I-neAvd-vd-IneA-vd-Ine-x3C0-r2-According to given data-v-x2032-d-1ne-x3C0-2r-2-v-x2032-d-141ne-x3C0-r2-vd-x2032-vd4

A current I flows through a uniform wire of diameter d when the electron drift velocity is V .The same current will flow through a wire of diameter d/2 made of the same material if the drift velocity of the electrons is
v/4
2v
v/2
4 v

The relation between current and drift velocity is

$I = n e A v_{d}$

$v_{d} = \frac{I}{n e A}$

$v_{d} = \frac{I}{n e π r^{2}}$

According to given data,

$v_{d}^{^{'}} = \frac{1}{n e π {(2 r)}^{2}}$

$v_{d}^{^{'}} = \frac{1}{4} \frac{1}{n e π r^{2}}$

${v_{d}}^{'} = \frac{v_{d}}{4}$

A current I flows through a uniform wire of diameter d when the electron drift velocity is V .The same current will flow through a wire of diameter d/2 made of the same material if the drift velocity of the electrons is v/42vv/24 v

The relation between current and drift velocity is I=neAvd vd=IneA vd=Ineπr2 According to given data, v′d=1neπ(2r)2 v′d=141neπr2 vd′=vd4

A current I flows through a uniform wire of diameter d when the electron drift velocity is V .The same current will flow through a wire of diameter d/2 made of the same material if the drift velocity of the electrons is
v/4
2v
v/2
4 v

The relation between current and drift velocity is

$I = n e A v_{d}$

$v_{d} = \frac{I}{n e A}$

$v_{d} = \frac{I}{n e π r^{2}}$

According to given data,

$v_{d}^{^{'}} = \frac{1}{n e π {(2 r)}^{2}}$

$v_{d}^{^{'}} = \frac{1}{4} \frac{1}{n e π r^{2}}$

${v_{d}}^{'} = \frac{v_{d}}{4}$