A current of 0-5 A flows through a resistance of 10 Omega dfrac-1-2- hour- Find the amount of electrical energy consumed by resistance-450 J4500 J45 J45000 J

Question

A current of 0-5 A flows through a resistance of 10 Omega dfrac-1-2- hour- Find the amount of electrical energy consumed by resistance-450  J4500  J45  J45000  J

Toppr Admin · Accepted Answer

Given-Current flowing through the resistor I-0-5-xA0-AResistance R-10-x3A9-Time for which current flows- t-12-xA0-hr-30min-30-xD7-60-xA0-s-1800-xA0-sBy Joule-apos-s law of heating- energy consumed by the resistance-E-I2RT-0-5-2-xD7-10-xD7-1800-xA0-xA0- -xA0- -4500-xA0-J

A current of $0.5 A$ flows through a resistance of $10 Ω$ for $\frac{1}{2}$ hour. Find the amount of electrical energy consumed by resistance.
$450 J$
$4500 J$
$45 J$
$45000 J$

Given:
Current flowing through the resistor $I = 0.5 A$
Resistance $R = 10 Ω$
Time for which current flows, $t = \frac{1}{2} h r = 30 m i n = 30 \times 60 s = 1800 s$
By Joule's law of heating, energy consumed by the resistance,
$E = I^{2} R T = {(0.5)}^{2} \times 10 \times 1800$
$= 4500 J$

A current of 0.5A flows through a resistance of 10Ω for 12 hour. Find the amount of electrical energy consumed by resistance.450 J4500 J45 J45000 J

Given:Current flowing through the resistor I=0.5 AResistance R=10ΩTime for which current flows, t=12 hr=30min=30×60 s=1800 sBy Joule's law of heating, energy consumed by the resistance,E=I2RT=(0.5)2×10×1800 =4500 J

A current of $0.5 A$ flows through a resistance of $10 Ω$ for $\frac{1}{2}$ hour. Find the amount of electrical energy consumed by resistance.
$450 J$
$4500 J$
$45 J$
$45000 J$

Given:
Current flowing through the resistor $I = 0.5 A$
Resistance $R = 10 Ω$
Time for which current flows, $t = \frac{1}{2} h r = 30 m i n = 30 \times 60 s = 1800 s$
By Joule's law of heating, energy consumed by the resistance,
$E = I^{2} R T = {(0.5)}^{2} \times 10 \times 1800$
$= 4500 J$