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Question

A current of 4.0 A is passed for 5 hours through 1L of 2M solution of nitrate using two nickel electrodes. The molarity of the solution at the end of the electrolysis will be:
  1. 1.2 M
  2. 2.0 M
  3. 1.5 M
  4. 2.5 M

A
1.5 M
B
2.0 M
C
1.2 M
D
2.5 M
Solution
Verified by Toppr

Ni2++2eNi
Faraday =4×5×60×6096500=0.746
Moles of Ni reduced =0.7462=0.373 mol
Moles of Ni2+ before reaction =2×1=2 mol
Left out =20.373=1.626
Molarity=MolesVolume=1.6261=1.626 molLit.

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