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Question

A current of 5A flows through a conductor. Calculate the number of electrons flowing through the conductor in 2s. [Take charge of electron as 1.6×1019
  1. 1.6×1019
  2. 6.25×1019
  3. 125×1018
  4. 16×1019

A
125×1018
B
16×1019
C
6.25×1019
D
1.6×1019
Solution
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Total charge that flows in 2s is given by

q=It=5×2=10C

Now, charge on one electron is given by e=1.6×1019C

N= number of electrons

q=Ne

N=qe

N=101.6×1019

N=6.25×1019

Answer-(B)

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