Question

A cylindrical container with diameter of base $$56\ cm$$ contains sufficient water to submerge a rectangular solid of iron with dimensions $$(32\ cm\times 22\ cm\times 14\ cm)$$. Find the rise in the level of water when the solid is completely submerged

Answer 1

Consider $$h\ cm$$ as the rise in level of water

We know that

Volume of cylinder of height $$h$$ and base radius $$28\ cm=$$ volume of rectangle iron solid

By substituting the values

$$\dfrac{22}{7}\times 28^2 \times h=32\times 22\times 14$$

On further calculation

$$22\times 28\times 4\times h=32\times 22\times 14$$

So we get

$$h=\dfrac{(32\times 22\times 14)}{ (22\times 28\times 4)}$$

By division

$$h=4cm$$

Therefore, the rise in the level of water when the solid is completely submerged is $$4 cm$$.