A dancer demonstrating dance steps along a straight line. The displacement time graph is given.
Find the average speed for the dance step depicted by CD.

$0.89 m s^{- 1}$
$1 m s^{- 1}$
$2 m s^{- 1}$
$2.75 m s^{- 1}$

Question

A dancer demonstrating dance steps along a straight line- The displacement time graph is given-Find the average speed the dance step depicted by CD-0-89  m s-1-1  m s-1-2  m s-1-2-75  m s-1-

Toppr Admin · Accepted Answer

Average speed is defined as the ratio of the distance covered to the total time taken .

Average speed $s_{a v} = \frac{D i s t a n c e c o v e r e d}{t i m e t a k e n}$

For step CD
Initial position is $4$ , final position is $0$ , hence distance covered $= 4 m$
Total time is $6 - 4 = 2 s e c$
So average speed is $s = \frac{4}{2} = 2 m / s$
So option $B$ is correct.

A dancer demonstrating dance steps along a straight line. The displacement time graph is given.Find the average speed for the dance step depicted by CD.0.89 ms−11 ms−12 ms−12.75 ms−1

Average speed is defined as the ratio of the distance covered to the total time taken .Average speed sav=Distance coveredtime takenFor step CD Initial position is 4, final position is 0, hence distance covered =4 mTotal time is 6−4=2 secSo average speed is s=42=2 m/sSo option B is correct.

A dancer demonstrating dance steps along a straight line. The displacement time graph is given.
Find the average speed for the dance step depicted by CD.

$0.89 m s^{- 1}$
$1 m s^{- 1}$
$2 m s^{- 1}$
$2.75 m s^{- 1}$