Question

A die is thrown 100 times and outcomes are noted as given below:

Outcome:	1	2	3	4	5	6
Frequency:	21	9	14	23	18	15

If a die is thrown at random, find the probability of getting a number less than 3.

Answer 1

We know that,

$$P(E)=\dfrac{n(E)}{n(S)}$$

where, $$P(E)$$ is the probability of an event $$E$$

$$n(E)$$ is the number of favorable outcomes and

$$n(S)$$ is the total number of trials.

Let $$E$$ be the event of getting a number less than $$3$$ i.e., $$1$$ or $$2$$.

Then, $$n(E)=21+9=30$$ and $$n(S)=100$$

$$\therefore P(E)=\dfrac{30}{100}=\dfrac3{10}$$