A die is thrown, find the probability of getting:
A number greater than $4$

$\text{Step-1: Find sample space and numbers of event.}$

                 $\text{Let S be the sample space.}$

                 $\text{S = 1, 2, 3, 4, 5, 6}$

                 $n(S)=6$

                 $\text{Let A be the probability of getting numbers greater than 4.}$

                 $\text{A = 5, 6}$

                 $n(A)=2$

$\text{Step-2: Find probability of getting numbers greater than 4.}$

                 $\text{Let P be the probability of getting than 4.}$

                 $P(A)=\frac{n(A)}{n(S)}=\frac{2}{6}=\frac{1}{3}$

$\text{Hence, the probability of getting numbers are greater than 4 is}$ $\frac{1}{3}.$