A die is thrown, find the probability of getting:
A number not greater than $4$ .

Question

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Answer 1

We know that
Number of favourable outcome= not greater than $4$ or numbers will be $1, 2, 3, 4$ which are $4$ in number
Here
$P (E) = \frac{N u m b e r o f f a v o u r a b l e o u t c o m e}{N u m b e r o f a l l p o s s i b l e o u t c o m e} = \frac{4}{6} = \frac{2}{3}$

Answer 2

We know that
Number of favourable outcome= not greater than

4

or numbers will be

1, 2, 3, 4

which are

4

in number
Here

P (E) = \frac{N u m b e r o f f a v o u r a b l e o u t c o m e}{N u m b e r o f a l l p o s s i b l e o u t c o m e} = \frac{4}{6} = \frac{2}{3}