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Question
A die is thrown, find the probability of getting: A number not greater than $$4$$.
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Solution
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We know that Number of favourable outcome= not greater than $$4$$ or numbers will be $$1,2,3,4$$ which are $$4$$ in number Here $$P(E)=\dfrac{Number\ of\ favourable\ outcome}{Number\ of\ all\ possible\ outcome}=\dfrac{4}{6}=\dfrac{2}{3}$$
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