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Question

A die is thrown, find the probability of getting:
A number not greater than $$4$$.

Solution
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We know that
Number of favourable outcome= not greater than $$4$$ or numbers will be $$1,2,3,4$$ which are $$4$$ in number
Here
$$P(E)=\dfrac{Number\ of\ favourable\ outcome}{Number\ of\ all\ possible\ outcome}=\dfrac{4}{6}=\dfrac{2}{3}$$

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