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In a throw of a dice,

Possible outcomes $$=\left\{1,2,3,4,5,6\right\}$$

Total number of possible outcomes $$=6$$

Now,

Favorable outcomes= number between $$3$$ and $$6=\left\{4,5\right\}$$

Number of favorable outcomes $$=2$$

Probability is given by,

$$\displaystyle P(A)$$$$=\dfrac{\text{no. of possible outcomes}}{\text{No. of total outcomes}}$$

$$P$$ (a number between $$3$$ and $$6$$) $$=\dfrac26=\dfrac13$$

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