Question

A die is thrown once. Find the probability of getting a number greater than $$2$$.

Answer 1

In a throw of a dice,

Possible outcomes $$=\left\{1,2,3,4,5,6\right\}$$

Total number of possible outcomes $$=6$$

Now,

Favorable outcomes= number greater than $$2=\left\{3,4,5,6\right\}$$

Number of favorable outcomes $$=4$$

Probability is given by,

$$\displaystyle P(A)$$$$=\dfrac{\text{no. of possible outcomes}}{\text{No. of total outcomes}}$$

$$P$$ (a number greater than $$2$$) $$=\dfrac 46=\dfrac23$$