A die is thrown once. Find the probability of getting a number greater than $2$.

In a throw of a dice,

Possible outcomes $=\left\{1,2,3,4,5,6\right\}$

Total number of possible outcomes $=6$

Now,

Favorable outcomes= number greater than $2=\left\{3,4,5,6\right\}$

Number of favorable outcomes $=4$

Probability is given by,

$P(A)$$=\frac{\text{no. of possible outcomes}}{\text{No. of total outcomes}}$

$P$ (a number greater than $2$) $=\frac{4}{6}=\frac{2}{3}$