Solve

Guides

Question

Open in App

Solution

Verified by Toppr

In a throw of a dice,

Possible outcomes $$=\left\{1,2,3,4,5,6\right\}$$

Total number of possible outcomes $$=6$$

Now,

Favorable outcomes=a number other than $$3=\left\{1,2,4,5,6\right\}$$

Number of favorable outcomes $$=5$$

Probability is given by,

$$\displaystyle P(A)$$$$=\dfrac{\text{no. of possible outcomes}}{\text{No. of total outcomes}}$$

$$P$$ (a number other than $$3$$) $$=\dfrac56$$

Was this answer helpful?

2