Question

A die is thrown once. Find the probability of getting a number other than $$3$$.

Solution
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In a throw of a dice,
Possible outcomes $$=\left\{1,2,3,4,5,6\right\}$$
Total number of possible outcomes $$=6$$

Now,
Favorable outcomes=a number other than $$3=\left\{1,2,4,5,6\right\}$$
Number of favorable outcomes $$=5$$

Probability is given by,
$$\displaystyle P(A)$$$$=\dfrac{\text{no. of possible outcomes}}{\text{No. of total outcomes}}$$

$$P$$ (a number other than $$3$$) $$=\dfrac56$$

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