A die is thrown once. Find the probability of getting a number greater than or equal to $4$ .

Question

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Answer 1

We know that,
In throwing a dice, total possible outcomes $= 1, 2, 3, 4, 5, 6$
So, $n (S) = 6$
On a dice, numbers greater than or equal to $4 = 4, 5, 6$
So, $n (E) = 3$
Hence, probability of getting a number greater than or equal to $4 = n (E) / n (S) = 3 / 6 = 1 / 2$

Answer 2

We know that,

In throwing a dice, total possible outcomes $= 1, 2, 3, 4, 5, 6$

So, $n (S) = 6$

On a dice, numbers greater than or equal to $4 = 4, 5, 6$

So, $n (E) = 3$

Hence, probability of getting a number greater than or equal to $4 = n (E) / n (S) = 3 / 6 = 1 / 2$