A die is thrown once- Find the probability of getting a number greater than or equal to 4-

Question

Toppr Admin · Accepted Answer

We know that-In throwing a dice- total possible outcomes - -1- 2- 3- 4- 5- 6-So- -n-S- - 6-160-On a dice- numbers greater than or equal to -4 - -4- 5- 6-So- n-E- - 3-Hence- probability of getting a number greater than or equal to -4 - n-E- n-S- - 3-6 - 1-2-

A die is thrown once. Find the probability of getting a number greater than or equal to $$4$$.

We know that,
In throwing a dice, total possible outcomes $$= {1, 2, 3, 4, 5, 6}$$
So, $$n(S) = 6$$
On a dice, numbers greater than or equal to $$4 = {4, 5, 6}$$
So,$$ n(E) = 3$$
Hence, probability of getting a number greater than or equal to $$4 = n(E)/ n(S) = 3/6 = 1/2$$

A die is thrown once. Find the probability of getting a number greater than or equal to $$4$$.

We know that,In throwing a dice, total possible outcomes $$= {1, 2, 3, 4, 5, 6}$$So, $$n(S) = 6$$ On a dice, numbers greater than or equal to $$4 = {4, 5, 6}$$So,$$ n(E) = 3$$Hence, probability of getting a number greater than or equal to $$4 = n(E)/ n(S) = 3/6 = 1/2$$

We know that,
In throwing a dice, total possible outcomes $$= {1, 2, 3, 4, 5, 6}$$
So, $$n(S) = 6$$
On a dice, numbers greater than or equal to $$4 = {4, 5, 6}$$
So,$$ n(E) = 3$$
Hence, probability of getting a number greater than or equal to $$4 = n(E)/ n(S) = 3/6 = 1/2$$